How Sergei Bobrovsky won the 2016-17 Vezina Trophy

NEWARK, NJ – MARCH 19: Sergei Bobrovsky #72 of the Columbus Blue Jackets looks on as he tends goal during the second period against the New Jersey Devils on March 19, 2017 at the Prudential Center in Newark, New Jersey. (Photo by Christopher Pasatieri/Getty Images)
NEWARK, NJ – MARCH 19: Sergei Bobrovsky #72 of the Columbus Blue Jackets looks on as he tends goal during the second period against the New Jersey Devils on March 19, 2017 at the Prudential Center in Newark, New Jersey. (Photo by Christopher Pasatieri/Getty Images)

LAS VEGAS – Columbus Blue Jackets netminder Sergei Bobrovsky won the 2017 Vezina Trophy Wednesday night, becoming the first two-time winner of the award since Tim Thomas did it with the Boston Bruins.

The award is voted on by the league’s 30 general managers.

During the regular season, Bobrovsky posted NHL leading numbers: 2.06 goal-against average and a .931 save-percentage. He was third in the NHL in shutouts (7) and third in wins at 41, which is a career high for the Blue Jackets’ goaltender.

In addition to his Vezina win, Bobrovsky nabbed a Hart Trophy nomination this season where he finished third behind Sidney Crosby and Connor McDavid, who won the award.

It’s no secret that Bobrovsky has struggled with confidence and health throughout his career. This season was a bounce-back he desperately needed. With his resurgence, Bobrovsky helped lead the Columbus Blue Jackets to their best season in franchise history, which included a 16-game win streak.

Bobrovsky was far and away the top choice for the Vezina, beating out an always impressive Braden Holtby and (when healthy) perennial nominee, Carey Price.

Here’s how the voting broke down:

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